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INTERACTIVE EXPLANATION

Where does energy go while ice melts?

Give water an energy budget. Watch its temperature and phase masses, catch a melting plateau, compare two starting states and inspect an open ice structure.

Enable JavaScript to change the conditions and run the interactive experiment.

Make a discovery

Heat can change a sample’s temperature—or its phase mixture. During melting at fixed pressure, the energy can change how much is liquid while the thermometer barely changes.

  • Follow heat into temperature change and phase change without losing energy at a boundary.
  • Find different phase mixtures at the same coexistence temperature.
  • Compare equal heat given to different masses or starting phases.
  • Keep H₂O identities intact through physical phase changes.
  • Explain why ordinary ice occupies more space than an equal mass of liquid water near melting.
  • Distinguish a constant-pressure energy model, an illustrative molecular scene and a real cup observation.

Make a prediction

A 0°C sample changes from 25% to 75% liquid by mass. Must the thermometer rise?

  • Yes, heat always raises temperature
  • No, energy can change the phase mixture
  • No, because no energy is needed
Read the explanation

For the virtual 100 g sample, converting an additional 50 g requires 16.670 kJ while the coexistence temperature stays approximately 0°C.

Understand it

Give the sample a budget

Heat is energy transferred because of a temperature difference. Our controls prescribe a net heat amount. The energy receipt shows which part warms a phase and which part changes the mixture. Temperature and transferred heat have different units and roles.

Catch the flat part

At the modeled melting temperature, adding heat increases liquid mass while temperature stays at approximately 0°C. A half-melted sample is not halfway to the boiling temperature. Pin two different mixtures with the same thermometer reading.

Spend the remainder

A heat pulse may first warm cold ice to melting, then melt some of it. Any energy left after a boundary still counts. The receipt carries it into the next interval rather than discarding it or pretending the ice instantly became warm liquid.

Keep the molecules together

Solid ice, liquid water and water vapor contain H₂O. Their arrangement and separation change. Boiling does not turn each water molecule into hydrogen gas and oxygen gas. A visible mist contains droplets; individual vapor molecules are not little white clouds.

Change the amount, change the response

The same heat shared by twice the single-phase mass produces half the temperature rise in this approximation. Phase-change budgets also scale with mass. Compare the curves per sample, then per kilogram.

Follow the heat out, too

Removing energy can freeze liquid or condense vapor. At an equilibrium plateau, the mixture changes without a temperature change. Zero net heat leaves the model’s temperature and phase masses fixed, even while the molecular illustration keeps moving.

Look closer at the science

The modeled system and boundary

Ordinary pure H₂O at nominal 101.325 kPa, retaining all mass with an ideal movable boundary. It represents uniform equilibrium states with pressure work only and negligible bulk kinetic/potential changes. It is not a rigid sealed vessel or an uncovered saucepan. At these conditions Q = ΔH, where H = U + pV; expansion work must not be subtracted a second time.

A declared constant-property approximation

The model uses rounded transition temperatures 0°C and 100°C, with a domain of −20°C to 120°C. Ice cₚ = 2020, liquid cₚ = 4180 and vapor cₚ = 2040 J/(kg·K). Fusion enthalpy is 333400 J/kg and vaporization enthalpy 2256400 J/kg. These are not a full IAPWS equation-of-state implementation.

Reference conditions stay attached

The ice capacity is a midpoint approximation to NIST’s −20, −10 and 0°C values. The vapor capacity comes from a 100–120°C enthalpy secant at 0.10 MPa. Vaporization enthalpy is tabulated at 100°C saturation and 101.42 kPa, slightly above the model’s nominal pressure. The constant-property choices and rounded transition points are explicitly approximate.

Decode energy, do not step a thermometer blindly

The enthalpy reference is ice at −20°C. For 100 g, interval boundaries are 4.040, 37.380, 79.180, 304.820 and 308.900 kJ. Within a single phase ΔT = Q/(mcₚ); within coexistence the converted mass is Q/L. A direct piecewise decoder preserves energy across any number of boundaries.

A plateau needs a phase fraction

At approximately 0°C, temperature alone does not distinguish 25% from 75% liquid by mass. Changing between those mixtures for 100 g requires 16.670 kJ in the supplied model. At vaporization, the fraction is also by mass—not the fraction of vessel volume occupied by vapor.

Mass, volume and water’s open solid structure

Near melting, reference densities are 916.7 kg/m³ for ice and 999.84 kg/m³ for liquid. Equal 100 g masses occupy about 109.09 and 100.02 mL. Freezing therefore increases volume by about 9.07% in this comparison. These two densities are not used to predict thermal expansion throughout the whole heating path.

Thermal motion is not the source of these computed numbers

The representative molecule positions never calculate temperature, pressure or phase fractions. Their motion is an illustration, not molecular dynamics. Zero Celsius is not zero thermal motion. A paused drawing does not mean a physically motionless solid.

Boiling is not the only route into air

Water can evaporate into surrounding air below its boiling temperature. That open-system mass and heat transfer lies outside this closed, equilibrium enthalpy path. Real heat-transfer rates, gradients, nucleation, supercooling and dissolved substances require additional physics.

A model boundary has an honest receipt

The lower and upper energy limits correspond to −20°C and 120°C in the supplied approximation. A requested pulse beyond a limit is split into accepted and unapplied energy. Unapplied energy is not transferred to the sample. Reversal uses accepted heat, not a request the model could not accept.

Where this is used

A cold reserve in a melting mixture

A phase change can absorb energy without a large temperature rise. The model explains that principle; predicting a real cold pack requires its material, quantity and heat-transfer conditions.

Read a heating graph properly

Its horizontal axis may be energy, energy per kilogram or time. Those choices make different claims. Our full energy axis preserves the much larger vaporization budget.

Understand ice near melting

Floating ice and freezing expansion invite a density question. A separate equal-mass volume comparison keeps that question distinct from the phase-fraction bar.

Try it yourself: Two surroundings, the same kind of ice

Supplies

  • Two similar clear, unbreakable open cups
  • Two small ordinary ice pieces from the same tray
  • About 100 mL room-temperature tap water
  • Spoon, tray and towel
  • Timer, paper and pencil
  • Optional suitable food thermometer
  1. Prepare two open cups

    Place them together on a tray indoors, away from strong drafts and direct sun. Label A and B. Note cup material and approximate ice sizes; similar-looking pieces are not necessarily equal mass.

  2. Change one surrounding

    Leave A without added liquid. Put about 100 mL room-temperature water in B. Predict how these different surroundings might affect melting and record a reason.

  3. Start the observation

    Use a spoon to place one ice piece in each cup at nearly the same time. Start the timer. Notice whether the piece in B floats; sketch it without pushing it under.

  4. Record what you can actually see

    Every two minutes for about 20 minutes, or until no solid is visible, record substantial ice, a smaller piece or no visible solid. A sketch is not a measurement of mass fraction. Retain incomplete melting observations too.

  5. Keep measurements attached to their method

    If using a suitable thermometer, optionally measure B after gentle consistent stirring, keeping the probe off the wall and visible ice. Record placement and instrument resolution. No particular temperature reading is required.

  6. Compare and explain differences

    Water, air and the cup can supply heat; size, contact and starting temperatures also matter. Compare the histories without promising a universal winner or completion time.

  7. Separate the observation from a calculation

    On paper, draw the virtual 100 g half-melted sample. The model needs 8.335 kJ to make it 75% liquid at about 0°C. Mark that as calculated, beside your observed table.

  8. Finish and state a limit

    Empty cups into a sink and wipe the tray. Explain why unknown room heat, initial ice temperature, dissolved substances and gradients prevent these observations from directly determining fusion enthalpy.

Where can the energy that melts ice come from?

Observe ordinary ice in open cups at room temperature. No boiling, sealed/heated vessel or pressure device. Do not drink the activity water. These uncontrolled observations do not measure latent heat or certify an ideal plateau.

Check your understanding

100 g at 0°C changes from 25% to 75% liquid. What changed?

  • Phase mixture and enthalpy, with temperature unchanged
  • The water became a new chemical substance
  • No energy entered
Answer and explanation

Phase mixture and enthalpy, with temperature unchanged Converting 50 g in the supplied model needs 0.050 × 333400 = 16670 J.

100 g and 200 g liquid samples start at 20°C and each receives 8.360 kJ. Their final temperatures are…

  • Both 40°C
  • 40°C and 30°C
  • 30°C and 40°C
Answer and explanation

40°C and 30°C With no phase boundary crossed, ΔT = Q/(mcₚ).

100 g of ice at −5°C receives 5.000 kJ. Which endpoint follows?

  • Liquid at about 12°C
  • All ice at 0°C, with the rest lost
  • About 88 g ice and 12 g liquid at 0°C
Answer and explanation

About 88 g ice and 12 g liquid at 0°C 1.010 kJ warms the ice; 3.990 kJ melts approximately 11.97 g.

What remains true when the representative water molecules enter the vapor view?

  • Each H₂O splits into H₂ and O₂
  • Each keeps its H₂O identity
  • Every water molecule grows larger
Answer and explanation

Each keeps its H₂O identity The phase change concerns organization and spacing rather than chemical decomposition.

Near 0°C, which comparison matches the reference densities?

  • 100 g ice ≈109 mL; 100 g liquid ≈100 mL
  • Every solid must occupy less space than its liquid
  • Melting removes about 9% of the mass
Answer and explanation

100 g ice ≈109 mL; 100 g liquid ≈100 mL Ordinary ice’s open structure gives a lower density than near-melting liquid water.

A half-melted equilibrium sample receives zero net heat. What should another display interval show?

  • The rest must melt because time passed
  • All molecular motion stops
  • Same temperature and phase masses, with thermal motion still represented
Answer and explanation

Same temperature and phase masses, with thermal motion still represented Macroscopic equilibrium can coexist with microscopic motion.

Why is the vaporization interval much wider on the full energy axis?

  • The supplied vaporization enthalpy is much larger than fusion enthalpy
  • Temperature secretly rises across the flat interval
  • New molecules are created
Answer and explanation

The supplied vaporization enthalpy is much larger than fusion enthalpy For 100 g, the two latent budgets are 225.64 and 33.34 kJ at their stated reference conditions.

Does the boiling plateau mean a damp cloth cannot dry at room temperature?

  • Yes, vapor can form only at exactly 100°C
  • No, evaporation into air below boiling is outside this closed path
  • No, the cloth changes water into a new substance
Answer and explanation

No, evaporation into air below boiling is outside this closed path An open evaporating cloth requires mass/heat-transfer physics absent from the retained equilibrium sample.

Sources and model limits

  • Pure ordinary H₂O, nominal fixed pressure and a movable closed-material boundary. No pressure control, rigid-vessel heating or home pressure apparatus is implied.
  • The rounded transition temperatures and constant properties are an educational approximation. Exact real melting/boiling points depend on pressure and the thermodynamic formulation.
  • The energy ledger computes equilibrium temperature and phase masses. It does not compute a melting front, individual molecule trajectories or an apparatus time-to-boil.
  • Representative molecule counts are rounded; phase mass fractions and the total mass ledger remain exact within floating-point arithmetic.
  • The diagram separates molecular views and uses scale breaks. Gas expansion is not constrained to fit the same literal liquid-sized container.
  • Vapor remains part of the retained material inventory. A white visible plume or mist is not a literal image of vapor molecules.
  • The near-melting density comparison is a separate reference card; its two density values are not a full thermal-expansion model.
  • The home activity observes ordinary ice in open cups. Uncontrolled room heat, unknown initial ice temperature and spatial gradients prevent direct validation of the ideal curve.

Source ice oxygen framework and its temperature

COD9015208, revision 292002; Fortes et al. (2004), J. Chem. Phys. 120, 11376–11379, DOI 10.1063/1.1765099. Powder neutron-diffraction refinement at 100 K. Oxygen symmetry expanded; half-occupied H sites omitted, not assigned unique orientations. Source CIF is preserved.

COD / Fortes et al. · Ice structural data

Real ice bubbles and grains, distinct from molecular-scale structure

Unmodified owner-linked original JPEG, USGS source marked Public Domain, approximately 2012. No instrument, optical method or scale is inferred.

USGS · Ice bubbles and crystals

Ordinary ice Ih thermodynamics and normal-pressure melting conditions

IAPWS R10-06(2009), release p. 3 and formulation verification tables. The constant-property lesson does not implement this complete equation of state.

IAPWS · Ice Ih formulation

Evaluated ice properties, fusion enthalpy and near-melting densities

Allan H. Harvey, Properties of Ice and Supercooled Water (2019), visible ordinary-H₂O tables at 101.325 kPa. Ice cₚ varies over the range; 2020 J/(kg·K) is the chosen midpoint approximation.

Harvey / NIST · Ice and supercooled water

Scientific basis for liquid/vapor equilibrium reference properties

IAPWS-95 revised release. This model uses narrow constant-property approximations rather than the full Helmholtz formulation.

IAPWS · Ordinary water formulation

Temperature scales, rounded boiling point and freezing expansion

First-party FAQs. Normal boiling is near 99.974°C on ITS-90; familiar 100°C is rounded here.

IAPWS · Water and steam FAQs

Constant-pressure heat, enthalpy and phase mass fractions

MIT thermodynamics textbook, chapter 3 §§3.2–3.2.2. Equations are independently implemented; source artwork is not redistributed.

MIT · Thermodynamics and Climate Change

Vaporization enthalpy at a disclosed nearby reference pressure

NISTIR 5078 Table 1, 100°C saturation row: 101.42 kPa and 2256.4 kJ/kg. Reference calculations, not a measured household heating trace.

Harvey / NIST · Saturation by temperature

Water vapor, mist and phase terminology

Official water-cycle terminology. The molecular illustration is not a photograph of steam.

USGS · Water-cycle glossary

Evaporation, condensation and dynamic equilibrium

Official vapor-pressure explanation. Open-cup evaporation is distinct from the lesson’s closed equilibrium path.

USGS · Vapor pressure and water

Independent subject review is pending.

Read the sources and model assumptions